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strugovaviktor
@strugovaviktor
July 2022
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25cos (п +2x )sin (3п-2x )=0
Решите уравнение ,очень срочноооооооо пожалуйста
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Answers & Comments
marishkoropar
Cos (п +2x )= -cos 2x
ф
ормули приведения
sin (3п-2x )= sin 2x
25cos (п +2x )sin (3п-2x )=0
25*(-cos 2x )*sin 2x =0
-12,5*2*cos 2x *sin 2x=0
-12,5*sin 4x=0
sin 4x=0
х=0, sin 0 =0
0 votes
Thanks 1
ln23
sin4x=0
4x=pi*n,n -целые
х=pi/4*n,n - целые
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Answers & Comments
формули приведения
sin (3п-2x )= sin 2x
25cos (п +2x )sin (3п-2x )=0
25*(-cos 2x )*sin 2x =0
-12,5*2*cos 2x *sin 2x=0
-12,5*sin 4x=0
sin 4x=0
х=0, sin 0 =0
4x=pi*n,n -целые
х=pi/4*n,n - целые