Решение и ответ:
[tex]\displaystyle 25=5\cdot5={5^2}[/tex]
[tex]\displaystyle {d^8}{t^{10}}={d^{2\cdot 4}}{t^{2\cdot 5}}={\left({{d^2}}\right)^4}{\left({{t^2}}\right)^5}[/tex]
[tex]\displaystyle 36=6\cdot 6={6^2}[/tex]
[tex]\displaystyle \frac{{{d^8}}}{{{t^{32}}}}=\frac{{{d^{2\cdot 4}}}}{{{t^{2\cdot 16}}}}=\frac{{{{\left({{d^2}}\right)}^4}}}{{{{\left({{t^2}}\right)}^{16}}}}[/tex]
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Answers & Comments
Решение и ответ:
[tex]\displaystyle 25=5\cdot5={5^2}[/tex]
[tex]\displaystyle {d^8}{t^{10}}={d^{2\cdot 4}}{t^{2\cdot 5}}={\left({{d^2}}\right)^4}{\left({{t^2}}\right)^5}[/tex]
[tex]\displaystyle 36=6\cdot 6={6^2}[/tex]
[tex]\displaystyle \frac{{{d^8}}}{{{t^{32}}}}=\frac{{{d^{2\cdot 4}}}}{{{t^{2\cdot 16}}}}=\frac{{{{\left({{d^2}}\right)}^4}}}{{{{\left({{t^2}}\right)}^{16}}}}[/tex]