25x^2-10x-3=0 решите пожалуйста). Created by misszarina01. algebra-ru

25x^2-10x-3=0 решите пожалуйста)...

Леорио Д= (-10)² - 4*25*3= 100+300=400
х1= 10+20/50= 30/50=0,6
х2= 10-20/50= -10/50=-0,2

2 votes Thanks 1

Akula17 $25 x^{2} - 10x-3=0$
$D=b2-4ac=(-10) ^{2} - 4*25*(-3)=100+300=400$
$\sqrt{D} = \sqrt{400} =20$
$x_{1}= \frac{10+20}{50} = \frac{30}{50} =0,6$
$x_{2} = \frac{10-20}{50} = \frac{-10}{50} = - 0,2$
Ответ:0,6; - 0,2

2 votes Thanks 1

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