25x+20x²+4x³=0 срочно. Created by fainabarinova94. algebra-ru

25x+20x²+4x³=0 срочно...

fainabarinova94 @fainabarinova94

August 2022 1 2 Report

25x+20x²+4x³=0 срочно

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ReMiDa

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Ответ:

$x_1 = 0 \\ x_2 = - 2.5$

$25x + 20 {x}^{2} + 4 {x}^{3} = 0 \\ x(4 {x}^{2} + 20x + 25) = 0$

произведение равно нулю когда один из множителей равен нулю:

$x1 = 0$

или

$4 {x}^{2} + 20x + 25 = 0 \\ \\ D = {b}^{2} - 4 ac = {20}^{2} - 4 \times 4 \times 25 = 400 - 400 = 0 \\ \\ x_2 = \dfrac{ - b}{2a} = \dfrac{ - 20}{2 \times 4} = - \dfrac{20}{8} = - \frac{5}{2} = - 2.5$

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