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МатерьДраконов
@МатерьДраконов
July 2022
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Найдите точку максимума функции y=(2x-3) cos x -2sin x +10
Принадлежащую промежутку (0;pi/2)
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sedinalana
Verified answer
Y`=2cosx-(2x-3)sinx-2cosx=-(2x-3)sinx=0
2x-3=0
2x=3
x=1,5
sinx=0
x=0∉(0;π/2)
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Answers & Comments
Verified answer
Y`=2cosx-(2x-3)sinx-2cosx=-(2x-3)sinx=02x-3=0
2x=3
x=1,5
sinx=0
x=0∉(0;π/2)