[tex]a_n=\frac{n^2}{n+1}\\\\a_2=\frac{2^2}{2+1}=\frac{4}{3}=1\frac{1}{3}\\\\a_6=\frac{6^2}{6+1}=\frac{36}{7}=5\frac{1}{7}\\\\a_{100}=\frac{100^2}{100+1}=\frac{10000}{101}=99\frac{1}{101}[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]a_n=\frac{n^2}{n+1}\\\\a_2=\frac{2^2}{2+1}=\frac{4}{3}=1\frac{1}{3}\\\\a_6=\frac{6^2}{6+1}=\frac{36}{7}=5\frac{1}{7}\\\\a_{100}=\frac{100^2}{100+1}=\frac{10000}{101}=99\frac{1}{101}[/tex]