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artemyhv
@artemyhv
August 2022
1
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Тригонометрия:
sin(pi-2x)-2cos(pi/2-2x)=корень из трех/2
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Kma86
Verified answer
Sin(pi-2x)-2cos(pi/2-2x)=√3
/2
sin2х-2sin2х=√3/2
-sin2х=
√3/2
sin2х=-
√3/2
2х=(-1)ⁿ (-π/3)+2πn, n∈Z
2х=(-1)ⁿ⁺¹
π/3+2πn, n∈Z
х=(-1)ⁿ⁺¹
π/6+πn, n∈Z
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Answers & Comments
Verified answer
Sin(pi-2x)-2cos(pi/2-2x)=√3/2sin2х-2sin2х=√3/2
-sin2х=√3/2
sin2х=-√3/2
2х=(-1)ⁿ (-π/3)+2πn, n∈Z
2х=(-1)ⁿ⁺¹ π/3+2πn, n∈Z
х=(-1)ⁿ⁺¹ π/6+πn, n∈Z