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July 2022 1 37 Report

Сложная производная
(Sin11x)'

Значение выражения ,содержащего радикалы
(6^-2*1/9)^-1/2

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NNNLLL54

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$(sin11x)'=11\cdot cos11x\\\\(6^{-2}\cdot \frac{1}{9})^{-\frac{1}{2}}=(\frac{1}{6^2}\cdot \frac{1}{3^2})^{-\frac{1}{2}}=((\frac{1}{6\cdot 3})^2)^{-\frac{1}{2}}=(\frac{1}{18})^{-1}=18$

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