Ответ:
[tex]125=5^3\ ,\ \ 27=3^3[/tex]
[tex]-\dfrac{125}{27}=\Big(-\dfrac{5}{3}\Big)\cdot \Big(-\dfrac{5}{3}\Big)\cdot \Big(-\dfrac{5}{3}\Big)[/tex]
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
[tex]125=5^3\ ,\ \ 27=3^3[/tex]
[tex]-\dfrac{125}{27}=\Big(-\dfrac{5}{3}\Big)\cdot \Big(-\dfrac{5}{3}\Big)\cdot \Big(-\dfrac{5}{3}\Big)[/tex]