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komisaruka
@komisaruka
May 2022
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знайдіть cosα,якщо sinα= -0,6 іπ<α<3π/2??7
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армения20171
Verified answer
Sina=-0,6;π<a<3π/2
cosa=?
cos²a= 1-sin²a=1-(-0,6)²=1-0,36=0,64
cosa<0;π<a<3π/2
cosa=-√0,64=-0,8
otvet cosa=-0,8
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Answers & Comments
Verified answer
Sina=-0,6;π<a<3π/2cosa=?
cos²a= 1-sin²a=1-(-0,6)²=1-0,36=0,64
cosa<0;π<a<3π/2
cosa=-√0,64=-0,8
otvet cosa=-0,8