освободитесь от иррациональности в знаменатиле дроби 10/√2+√7 пж срочно. Created by treshreclama. algebra-ru

√2+√7 пж срочно...

treshreclama @treshreclama

July 2022 1 37 Report

освободитесь от иррациональности в знаменатиле дроби 10/√2+√7 пж срочно

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blackmday12

Объяснение:

$\frac{10}{ \sqrt{2} + \sqrt{7} } = \frac{10 \times ( \sqrt{2} - \sqrt{7}) }{( \sqrt{2} + \sqrt{7} )( \sqrt{2} - \sqrt{7}) } = \frac{10 \times ( \sqrt{2} - \sqrt{7}) }{2 - 7} = \frac{10( \sqrt{2} - \sqrt{7} )}{ - 5} = - 2( \sqrt{2} - \sqrt{7} )$

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