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elenakozlova841
@elenakozlova841
July 2022
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помогите решить
sin x/3 = -1/2
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friendyou20
Sinx/3=-1/2
x/3=(-1)^(n+1)*пи/6+пи*n, n принадлежит Z (умножить все на 3)
x=(-1)^(n+1)*пи/2+3*пи*n, n принадлежит Z
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Answers & Comments
x/3=(-1)^(n+1)*пи/6+пи*n, n принадлежит Z (умножить все на 3)
x=(-1)^(n+1)*пи/2+3*пи*n, n принадлежит Z