[tex]\displaystyle 1)\frac{(3^3)^2}{3^4*9}:\frac{1}{81}=\frac{3^6}{3^4*9}*81=3^2*9=3^2*3^2=3^4=81\\ \\2)\frac{18^3*30^2}{45*12^2}=\frac{5832*900}{45*144}=\frac{5832*900}{6480}=\frac{9*900}{10}=9*90=810[/tex]