Ответ:
[tex]{Al}^{27}_{13} + {n}^{10}_{0}[/tex]⇒[tex]{Na}^{33}_{11} + {He}^{4}_{2}[/tex]
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Ответ:
[tex]{Al}^{27}_{13} + {n}^{10}_{0}[/tex]⇒[tex]{Na}^{33}_{11} + {He}^{4}_{2}[/tex]