sin ( 2pi/3) + sin pi + sin (pi/6) + sin (3pi/2)
sin ( 2pi/3) + sin pi + sin (pi/6) + sin (3pi/2)= +0+1/2-1 =
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sin ( 2pi/3) + sin pi + sin (pi/6) + sin (3pi/2)=
+0+1/2-1 = ![(\sqrt{3}-1)/2 (\sqrt{3}-1)/2](https://tex.z-dn.net/?f=%28%5Csqrt%7B3%7D-1%29%2F2)