275. V1) (3x – 4|< 5;
4) 15 - 4x[<1;
2) (2x +3|< 3;
5) |4x – 1l<7;
3) (2 – 3x < 2;
6) |3 – 2xl <3.
Решите неравенство номер 275 ,276
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