((1/3)b+a)((1/9)b²-(1/3)ba+a²)-(1/27)b³= ((1/3)b)³+ а³- ((1/3)b)³ = а³
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((1/3)b+a)((1/9)b²-(1/3)ba+a²)-(1/27)b³= ((1/3)b)³+ а³- ((1/3)b)³ = а³