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lenaalekseeva565
@lenaalekseeva565
July 2022
2
6
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Помогите пожалуйста решить:
а) √26² - 10²
б) √7/√28²-21²
в) √50•12•6
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лолкек4ебурек
А) 26 - 100=74
б) 1/4√7 - 441 = √7/28-441=√7-12348/28
в)√(25×2)×12×6=2√2×12×6=144√2
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Belochka12345678
А)√26² - 10² =√676=26-10=16
б)√7/√28²-21²=
28-21=7
в)
√50•12•6=
√
3600=60
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Answers & Comments
б) 1/4√7 - 441 = √7/28-441=√7-12348/28
в)√(25×2)×12×6=2√2×12×6=144√2
б)√7/√28²-21²= 28-21=7
в)√50•12•6=√3600=60