[tex]\displaystyle\bf\\\Big(4,75-\frac{1}{8}\Big):0,8-\Big(4,75-2,125\Big):0,8=\frac{4,75-\frac{1}{8} -4,75+2,125}{0,8} =\\\\\\=\frac{2\frac{1}{8}-\frac{1}{8} }{0,8} =\frac{2}{0,8} =\frac{2\cdot 10}{8} =2,5[/tex]
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[tex]\displaystyle\bf\\\Big(4,75-\frac{1}{8}\Big):0,8-\Big(4,75-2,125\Big):0,8=\frac{4,75-\frac{1}{8} -4,75+2,125}{0,8} =\\\\\\=\frac{2\frac{1}{8}-\frac{1}{8} }{0,8} =\frac{2}{0,8} =\frac{2\cdot 10}{8} =2,5[/tex]