Verified answer

Ответ:

[tex]2 \sin \frac{\pi}{6} \cos \frac{\pi}{6} + \frac{3}{6} [/tex]

[tex] \cos \frac{\pi}{6} = \frac{ \sqrt{3} }{2} [/tex]

=>

[tex]2 \sin \frac{\pi}{6} \cos \frac{\pi}{6} + \frac{3}{2} = 2 \times \frac{1}{2} \times \frac{ \sqrt{3} }{2} + \frac{3}{6} = \frac{ \sqrt{3} }{3} + \frac{3}{6} = \frac{\sqrt{3}+3} {6} =\frac{1}{2} + \frac{3}{6} = \frac{3}{6} + \frac{3}{6} = \frac{6}{6} = 1 \\ [/tex]