Home
О нас
Products
Services
Регистрация
Войти
Поиск
sayndwif
@sayndwif
September 2021
1
0
Report
288 Помогите пожалуйста в заранее спасибо!
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
hlopushinairina
1)sinα=3/5;
cosα=⁺₋√(1-sin²α)=₊⁺√1-9/25=⁺₋√16/25=⁺₋4/5;
tgα=sinα/cosα=⁺₋3/5:4/5=⁺₋3/5·5/4=⁺₋3/4;
ctgα=1/tgα=⁺₋1:3/4=⁺₋4/3;
2)sinα=40/41;
cosα=⁺₋√1-1600/1681=⁺₋√81/1681=⁺₋9/41;
tgα=sinα/cosα=40/41:(⁺₋9/41)=⁺₋40/9;
ctgα=1/tgα=⁺₋9/40;
3)sinα=0.5;
cosα=⁺₋√1-0.25=⁺₋√0.75=⁺₋0.5√3;
tgα=⁺₋0.5/0.5√3=⁺₋√3/3;
ctgα=⁺₋0.5√3/0.5=√3;
0 votes
Thanks 1
More Questions From This User
See All
sayndwif
September 2021 | 0 Ответы
5...
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "288 Помогите пожалуйста в заранее спасибо!..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
cosα=⁺₋√(1-sin²α)=₊⁺√1-9/25=⁺₋√16/25=⁺₋4/5;
tgα=sinα/cosα=⁺₋3/5:4/5=⁺₋3/5·5/4=⁺₋3/4;
ctgα=1/tgα=⁺₋1:3/4=⁺₋4/3;
2)sinα=40/41;
cosα=⁺₋√1-1600/1681=⁺₋√81/1681=⁺₋9/41;
tgα=sinα/cosα=40/41:(⁺₋9/41)=⁺₋40/9;
ctgα=1/tgα=⁺₋9/40;
3)sinα=0.5;
cosα=⁺₋√1-0.25=⁺₋√0.75=⁺₋0.5√3;
tgα=⁺₋0.5/0.5√3=⁺₋√3/3;
ctgα=⁺₋0.5√3/0.5=√3;