Объяснение:
m(H2O)=Vp=280×1=280г
w(глюКози)=m(розч)×w(глюкози)×100%/(m(розч)+m(Н2О)= (720×0.25)×100%/(720+280)=18%
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Объяснение:
m(H2O)=Vp=280×1=280г
w(глюКози)=m(розч)×w(глюкози)×100%/(m(розч)+m(Н2О)= (720×0.25)×100%/(720+280)=18%