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alievmax
@alievmax
October 2021
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Решить неравенства:
1. 2sin2x>-√2
2. cosπx>1/2
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Аксауле1
1)2sin2x>-корень2
2/2sin2x>-корень2/2
sin2x>-корень2/2
arcsin-корень2/2+2Пk(-П/6+Пk;5П/8+Пk)
2)cosПх>1/2
-arccos1/2+2Пk<П(-П/3+2П/П:П/3+2П/П)
2 votes
Thanks 1
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Answers & Comments
2/2sin2x>-корень2/2
sin2x>-корень2/2
arcsin-корень2/2+2Пk(-П/6+Пk;5П/8+Пk)
2)cosПх>1/2
-arccos1/2+2Пk<П(-П/3+2П/П:П/3+2П/П)