28pxy...

alim072000 @alim072000

July 2022 1 6 Report

(3p^2mq/2a^2b^2×3abc/8x^2y^2):9a^2b^2c^3/28pxy

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Yena

Verified answer

$(\frac{3p^2mq}{2a^2b^2}*\frac{3abc}{8x^2y^2}):\frac{9a^2b^2c^3}{28pxy}=\frac{9cmp^2q}{16abx^2y^2}*\frac{28pxy}{9a^2b^2c^3}=\frac{7mp^3q}{4a^3b^3c^2xy}$

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