Дана функция y = f(x), где f(x)= - 3x + 2. Найдите:a) f(0), f(2/3), f(-3), f(-1/2)
f(0)=-3*0+2=2f(2/3)=-3*2/3+2=0f(-3)=-3*(-3)+2= 11
f(-1/2)=-3*(-1/2)+2=3/2+2=1,5+2=3,5
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f(0)=-3*0+2=2
f(2/3)=-3*2/3+2=0
f(-3)=-3*(-3)+2= 11
f(-1/2)=-3*(-1/2)+2=3/2+2=1,5+2=3,5