Итак.Помогите. Пять целых две третих в нулевой степени + (-1/2)^-2+4^1/2. Created by Sok3232. matematika-ru

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July 2022 1 13 Report

Итак.Помогите.
Пять целых две третих в нулевой степени + (-1/2)^-2+4^1/2

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matilda17562 Решение:
$(5 \frac{2}{3}) ^{0} + ( - \frac{1}{2})^{-2} + 4^{ \frac{1}{2} } = 1 + ( - 2)^{2} + ( 2^{2} )^{ \frac{1}{2} } = 1 + 4 + 2 = 7.$
Ответ: 7.

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