[tex]\displaystyle \frac{x-3}{x+5}=\frac{5}{8},x\neq -5\\ \\8(x-3)=5(x+5)\\8x-24=5x+25\\8x-5x=25+24\\3x=49\\\\x=\frac{49}{3}=16\frac{1}{3}[/tex]
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[tex]\displaystyle \frac{x-3}{x+5}=\frac{5}{8},x\neq -5\\ \\8(x-3)=5(x+5)\\8x-24=5x+25\\8x-5x=25+24\\3x=49\\\\x=\frac{49}{3}=16\frac{1}{3}[/tex]