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Edim
@Edim
August 2022
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cos (П + х/2) = 0
sin (П/2 + x) = 1
cos (П/3 - x) = кор. из 2/2
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oganesbagoyan
Verified answer
cos(π+x/2) =0 ;
π+x/2 =π/2+π*k , k∈
Z.
x/2 = - π/2 +π*k;
x= -π+2π*k;
x=(2k -1)π;
нечетное число π
================
sin(π/2+x) =1;
π/2+x =π/2 +2π*k;
x =2k*π
. четное число π
================
cos(
π/3 -x) =√2/2;
cos(x-π/3) =√2/2;( cos четная фунлция)
x-π/3 =(+/-)π/4 +2π*
x₁= π/3+(+/-)π/4 +2π*k;
или
x₁ = 7π/12+2π*k;
x₂ = π/12+2π*k;
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Answers & Comments
Verified answer
cos(π+x/2) =0 ;π+x/2 =π/2+π*k , k∈ Z.
x/2 = - π/2 +π*k;
x= -π+2π*k;
x=(2k -1)π; нечетное число π
================
sin(π/2+x) =1;
π/2+x =π/2 +2π*k;
x =2k*π. четное число π
================
cos(π/3 -x) =√2/2;
cos(x-π/3) =√2/2;( cos четная фунлция)
x-π/3 =(+/-)π/4 +2π*
x₁= π/3+(+/-)π/4 +2π*k;
или
x₁ = 7π/12+2π*k;
x₂ = π/12+2π*k;