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sashenkabeleho
@sashenkabeleho
July 2022
1
18
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Найдите косинус а если синус а 7/25 и а принадлежит (0;П/2)
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AsanJ
Cosα=√(1-sin²α)=√(1-49/625)=√625/625-49/625)=√(625-49)/625=√576/625=+-24/25
cosα>0, т.к α∈(0; π/2) => cosα=+24/25
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cosα>0, т.к α∈(0; π/2) => cosα=+24/25