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xwxsanaxwx
@xwxsanaxwx
August 2022
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Дана функция у=f(x), где f(x)=-6x^2. Найдите f(1/2a + 2), 2f(x^2 - 1)
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IrkaShevko
Verified answer
1) f(0.5a + 2) = -6(0.5a+2)^2 = -1.5a^2 - 6a -24
2) 2f(x^2 - 1) = -12(x^2 - 1)^2 = -12x^4 +24x^2 - 12
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Answers & Comments
Verified answer
1) f(0.5a + 2) = -6(0.5a+2)^2 = -1.5a^2 - 6a -242) 2f(x^2 - 1) = -12(x^2 - 1)^2 = -12x^4 +24x^2 - 12