выполните преобразования (2/а-2 - 3а+6/а^2+а-6 + 2а/а+3)* а/2а-5. Created by Theee. algebra-ru

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выполните преобразования (2/а-2 - 3а+6/а^2+а-6 + 2а/а+3)* а/2а-5

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artalex74 $\frac{2(a+3)-(3a+6)+2a(a-2)}{(a-2)(a+3)}*\frac{a}{2a-5}=\frac{2a+6-3a-6+2a^2-4a}{(a-2)(a+3)}*\frac{a}{2a-5}=\\ =\frac{2a^2-5a}{(a-2)(a+3)}*\frac{a}{2a-5}=\frac{a(2a-5)}{(a-2)(a+3)}*\frac{a}{2a-5}=\frac{a^2}{a^2+a-6}$

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