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svetochka01052000
@svetochka01052000
August 2022
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(2а+1)(8а-1)+(4а-5)(3-2а)+12 при а=0
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n1982
(2*0+1)(8*0-1)+(4*0-5)(3-2*0)+12=-1-15+12=-4
1 votes
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stifler007
1*(-1)+(-5)*3+12=-4 ответ
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