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BlackTea133
@BlackTea133
July 2022
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(2a–3x)²+(x–1)²=10(x–2)(x+2)
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sedinalana
4a²-12ax+9x²+x²-2x+1-10x²+40=0
4a²+41=2x+12ax
x(2+12a)=4a²+41
x=(4a²+41)/(2+12a)
a=-1/6 нет решения
1 votes
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sL1nky
4a²-9x²+21+1 так наверное
0 votes
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Answers & Comments
4a²+41=2x+12ax
x(2+12a)=4a²+41
x=(4a²+41)/(2+12a)
a=-1/6 нет решения