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VovkaBar583
@VovkaBar583
July 2022
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Найдите область определения функции y=x/(x-2)^(1/2)
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Алкадиеныч
Verified answer
X-2>=0
x-2≠0
x≥2
x≠2
Ответ: (2; + беск)
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VovkaBar583
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Answers & Comments
Verified answer
X-2>=0x-2≠0
x≥2
x≠2
Ответ: (2; + беск)