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SVETA200011
@SVETA200011
July 2022
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2а(а+б-с)-2б(а-б-с)+2с(а-б+с)
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kratgv
Verified answer
2а(а+б-с)-2б(а-б-с)+2с(а-б+с)=2а²+2аб-2ас-2аб+2б²+2бс+2ас-2бс+2с²=
2а²+2б²+2с²=2·(
а²+б²+с²)
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Verified answer
2а(а+б-с)-2б(а-б-с)+2с(а-б+с)=2а²+2аб-2ас-2аб+2б²+2бс+2ас-2бс+2с²=2а²+2б²+2с²=2·(а²+б²+с²)