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sorokinaanastasia
@sorokinaanastasia
August 2022
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Помогите решить пожалуйста cos5x=√2/2
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nikoly2007
Cos5x=√2/2
используя формулу решения простейших тригонометрических уравнений
cosx = a
x =±arccosa+2πk (k€Z)
имеем:
5x = ±arccos (√2/2)+2πk (k€Z)
5x= π/4 + 2πk (k€Z)
x= π/20 + 2πk/5 (k€Z)- ответ
1 votes
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Answers & Comments
используя формулу решения простейших тригонометрических уравнений
cosx = a
x =±arccosa+2πk (k€Z)
имеем:
5x = ±arccos (√2/2)+2πk (k€Z)
5x= π/4 + 2πk (k€Z)
x= π/20 + 2πk/5 (k€Z)- ответ