Home
О нас
Products
Services
Регистрация
Войти
Поиск
egorvas77
@egorvas77
July 2022
1
4
Report
решите пожалуйста
log1/3 (x-2)>1/(log1/3 (x-2))+3/2
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
Verified answer
ОДЗ
x-2>0⇒x>2
log(1/3)(x-2)=a
a>1/a+3/2
(2a²-2-3a)/a>0
2a²-3a-2=0
D=9+16=25
a1=(3-5)/4=-1/2
a2=(3+5)/4=2
a<-1/2⇒log(1/3)(x-2)<-1/2⇒x-2>√3⇒x>2+√3
a>2⇒log(1/3)(x-2)>2⇒x-2<1/9⇒x<2 1/9
x∈(2;2 1/9) U (2+√3;∞)
2 votes
Thanks 1
More Questions From This User
See All
egorvas77
July 2022 | 0 Ответы
4...
Answer
egorvas77
July 2022 | 0 Ответы
8)...
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "2..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
ОДЗx-2>0⇒x>2
log(1/3)(x-2)=a
a>1/a+3/2
(2a²-2-3a)/a>0
2a²-3a-2=0
D=9+16=25
a1=(3-5)/4=-1/2
a2=(3+5)/4=2
a<-1/2⇒log(1/3)(x-2)<-1/2⇒x-2>√3⇒x>2+√3
a>2⇒log(1/3)(x-2)>2⇒x-2<1/9⇒x<2 1/9
x∈(2;2 1/9) U (2+√3;∞)