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12makonya12
@12makonya12
August 2022
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cos²(π-α)+sin²(π/2-α)+cos(π+α)cos(2π-α)/tg²(α-π/2)ctg²(3π/2+α)=cos²α
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pomoshnik09
cos²α+cos²α+(-cosα*cosα)/ctg²αtg²α=cos²α/1=cos²α
тождество верно
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тождество верно