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1Vendetta7
@1Vendetta7
July 2022
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1)Arccos(-√2/2)+arcsin(-1)
2)arctg1+arcctg√3
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banukenzhebek
1) arccos(-√2/2)+arcsin(-1)=3π/4-π/2=(3π-2π)/4=π/4
2)arctg1+arcctg√3=π/4+π/6=(3π+2π)/12=5π/12
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Answers & Comments
2)arctg1+arcctg√3=π/4+π/6=(3π+2π)/12=5π/12