Помогите с тождеством tg(π-α)÷cos(π+α)×sin(3π/2+α)/tg(3π/2+α)=tg²α. Created by totalwar5555. algebra-ru

2+α)=tg²α...

August 2022 1 14 Report

Помогите с тождеством
tg(π-α)÷cos(π+α)×sin(3π/2+α)/tg(3π/2+α)=tg²α

Answers & Comments

nKrynka Решение
tg(π-α)/cos(π+α)×sin(3π/2+α)/tg(3π/2+α) = tg²α
tg(π-α)/cos(π+α)×sin(3π/2+α)/tg(3π/2+α) =[ - tgα / ( - cosα)*( - cosα)] / (- ctgα) = (sinx*sinx*cosx) / (cos^2x*cosx) = tg^2x

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chto znachit udelnoe soprotivlenie konstanta 4710 7 ommdlya kakih celej ispol

dajte nazvanie sleduyushim spirtam po pravilam sistematicheskoj nomenklatury

napishite kratkie strukturnye formuly soedinenij po ih nazvaniyam a 2 metilgepta

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