[tex]-(7,76-6\frac{8}{9})-(0,24-2\frac{1}{9} ) =?[/tex]
[tex]1)[/tex] [tex]7,76-6\frac{8}{9}=7\frac{19}{25}-6\frac{8}{9}=(7-6)+( \frac{19}{25}-\frac{8}{9})=1+\frac{171-200}{25*9} = 1-\frac{29}{225} =\frac{196}{225}[/tex]
[tex]2)[/tex] [tex]-(\frac{196}{225} )= -\frac{196}{225}[/tex]
[tex]3)[/tex] [tex]0,24-2\frac{1}{9} =\frac{6}{25} -2\frac{1}{9} =(0-2)+(\frac{6}{25} -\frac{1}{9} )=-2+\frac{54-25}{25*9} =-2+\frac{29}{225}=-1 \frac{196}{225}[/tex]
[tex]4)[/tex] [tex]- \frac{196}{225} -(-1 \frac{196}{225} )=- \frac{196}{225} +1 \frac{196}{225} =1[/tex]
Ответ: [tex]1.[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]-(7,76-6\frac{8}{9})-(0,24-2\frac{1}{9} ) =?[/tex]
[tex]1)[/tex] [tex]7,76-6\frac{8}{9}=7\frac{19}{25}-6\frac{8}{9}=(7-6)+( \frac{19}{25}-\frac{8}{9})=1+\frac{171-200}{25*9} = 1-\frac{29}{225} =\frac{196}{225}[/tex]
[tex]2)[/tex] [tex]-(\frac{196}{225} )= -\frac{196}{225}[/tex]
[tex]3)[/tex] [tex]0,24-2\frac{1}{9} =\frac{6}{25} -2\frac{1}{9} =(0-2)+(\frac{6}{25} -\frac{1}{9} )=-2+\frac{54-25}{25*9} =-2+\frac{29}{225}=-1 \frac{196}{225}[/tex]
[tex]4)[/tex] [tex]- \frac{196}{225} -(-1 \frac{196}{225} )=- \frac{196}{225} +1 \frac{196}{225} =1[/tex]
Ответ: [tex]1.[/tex]