[tex]\displaystyle\bf\\2Sin\Big(\frac{3\pi }{2} +\beta \Big)\cdot Sin\Big(\pi -\beta \Big)=-2Cos\beta \cdot Sin\beta =-Sin2\beta[/tex]
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[tex]\displaystyle\bf\\2Sin\Big(\frac{3\pi }{2} +\beta \Big)\cdot Sin\Big(\pi -\beta \Big)=-2Cos\beta \cdot Sin\beta =-Sin2\beta[/tex]