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ЕкатеринаБелоусова
@ЕкатеринаБелоусова
July 2022
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определить значение остальных тригонометрических функций аргумента a, если дано :
sina 4/5 и 0<a<п/2
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nKrynka
Cosa = √(1 - sin²a)
cosa = √(1 - (4/5)²) = √(9/25) = 3/5
tgx = sinx / cosx
tgx = (3/5) : (4/5) = 3/4
ctgx = 1/ tgx = 4/3
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Answers & Comments
cosa = √(1 - (4/5)²) = √(9/25) = 3/5
tgx = sinx / cosx
tgx = (3/5) : (4/5) = 3/4
ctgx = 1/ tgx = 4/3