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Liseno4ek00
@Liseno4ek00
July 2022
1
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Найдите cos a , если sin a = ((2sqrt(6))/ 5) и pi/2 < a < 3pi/2
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natyak
Cosα=+-√1-sin²α=+-√1-4*6/25=+-√1-24/25=+-√1/25=+-1/5
так как α∈2 и 3 четвертям то cosα=-1/5
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так как α∈2 и 3 четвертям то cosα=-1/5