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sassan
@sassan
November 2021
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СРОЧНО! 5arccos1 - 6arcsin(- 1) + 3arctg1 + 2arccos(- корень 3/2).
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Lesben
Arcos1 =0 , (cos 0=1)
arcsin(-1)=3pí/2 , sin (3pí/2)=-1
arctg 1 = pí/4 , tg (pí/4)=1
arccos(-V3/2)´=5pí/6 , cos 5pí/6=-V3/2
5.arccos1 -6.arcsin(-1)+3.arctg 1 + 2.arccos(-V3/2)=
=5.0 -6.3pí/2 +3.pí/4 -2.V3/2=
=0-9.pí +3pí/4-V3=-36pí/4+3pí/4 -V3=-33pí/4 -V3
2 votes
Thanks 2
sassan
Красно дякую.
Lesben
Net za čto. Do cvidanija!
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Answers & Comments
arcsin(-1)=3pí/2 , sin (3pí/2)=-1
arctg 1 = pí/4 , tg (pí/4)=1
arccos(-V3/2)´=5pí/6 , cos 5pí/6=-V3/2
5.arccos1 -6.arcsin(-1)+3.arctg 1 + 2.arccos(-V3/2)=
=5.0 -6.3pí/2 +3.pí/4 -2.V3/2=
=0-9.pí +3pí/4-V3=-36pí/4+3pí/4 -V3=-33pí/4 -V3