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gajnullina98
@gajnullina98
July 2022
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решите уравнение sin2x=sin(x+п/2)
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evaromanova19
X1 = -i*log(-sqrt(3)/2 + i/2)x2 = -i*log(sqrt(3)/2 + i/2)x3 = -pi/2x4 = pi/2x1 = -i*log(-sqrt(3)/2 + i/2)x2 = -i*log(sqrt(3)/2 + i/2)x3 = -pi/2x4 = pi/2x1 = -i*log(-sqrt(3)/2 + i/2)x2 = -i*log(sqrt(3)/2 + i/2)x3 = -pi/2
x4 = pi/2
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