решите уравнение sin2x=sin(x+п/2). Created by gajnullina98. matematika-ru

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July 2022 1 10 Report

решите уравнение sin2x=sin(x+п/2)

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evaromanova19 X1 = -i*log(-sqrt(3)/2 + i/2)x2 = -i*log(sqrt(3)/2 + i/2)x3 = -pi/2x4 = pi/2x1 = -i*log(-sqrt(3)/2 + i/2)x2 = -i*log(sqrt(3)/2 + i/2)x3 = -pi/2x4 = pi/2x1 = -i*log(-sqrt(3)/2 + i/2)x2 = -i*log(sqrt(3)/2 + i/2)x3 = -pi/2x4 = pi/2

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