Home
О нас
Products
Services
Регистрация
Войти
Поиск
vipkatyakisel
@vipkatyakisel
May 2021
1
25
Report
Вычислите определенный интеграл наверху П/4 интеграл внизу п/12 умножить 3dx/ 2cos^2 3x
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
volodyk
Verified answer
∫(3/2cos²3x)dx=3/2*(1/3*tg3x)=1/2*tg3x=1/2*(tg(3*π/4) - tg(3*π/12))=1/2*(-tgπ/4-tgπ/4)=1/2*(-2tgπ/4)=1/2*(-2)=-1
2 votes
Thanks 2
More Questions From This User
See All
vipkatyakisel
August 2022 | 0 Ответы
x^3...
Answer
vipkatyakisel
July 2022 | 0 Ответы
lim xgt0 sin8x7x reshite
Answer
vipkatyakisel
May 2021 | 0 Ответы
3sin^2x...
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "2cos^2 3x..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
∫(3/2cos²3x)dx=3/2*(1/3*tg3x)=1/2*tg3x=1/2*(tg(3*π/4) - tg(3*π/12))=1/2*(-tgπ/4-tgπ/4)=1/2*(-2tgπ/4)=1/2*(-2)=-1