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vipkatyakisel
@vipkatyakisel
May 2021
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Вычислите определенный интеграл наверху П/4 интеграл внизу п/12 умножить 3dx/ 2cos^2 3x
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volodyk
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∫(3/2cos²3x)dx=3/2*(1/3*tg3x)=1/2*tg3x=1/2*(tg(3*π/4) - tg(3*π/12))=1/2*(-tgπ/4-tgπ/4)=1/2*(-2tgπ/4)=1/2*(-2)=-1
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∫(3/2cos²3x)dx=3/2*(1/3*tg3x)=1/2*tg3x=1/2*(tg(3*π/4) - tg(3*π/12))=1/2*(-tgπ/4-tgπ/4)=1/2*(-2tgπ/4)=1/2*(-2)=-1