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queenplay
@queenplay
August 2022
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2cos^2x-sin2x=0 решить уравнение
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sedinalana
Verified answer
2сos²x-2sinxcosx=0
2cosx(cosx-sinx)=0
cosx=0⇒x=π/2+πn,n∈z
cosx-sinx=0/cosx
1-tgx=0
tgx=1⇒x=π/4+πk,k∈z
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Answers & Comments
Verified answer
2сos²x-2sinxcosx=02cosx(cosx-sinx)=0
cosx=0⇒x=π/2+πn,n∈z
cosx-sinx=0/cosx
1-tgx=0
tgx=1⇒x=π/4+πk,k∈z