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xzloyx
@xzloyx
July 2022
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2cos2x+2cosxsin^2x=cosx
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mymurkin
2cos2x-cosx(1-2sin^2x)=0
2cos2x-cosx*cos2x=0
cos2x(2-cosx)=0
cos2x=0 2-cosx=0
2x=π/2+πn корней нет
x=π/4+πn/2
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xzloyx
Спасибо вам!)
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Answers & Comments
2cos2x-cosx*cos2x=0
cos2x(2-cosx)=0
cos2x=0 2-cosx=0
2x=π/2+πn корней нет
x=π/4+πn/2