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August 2022
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2cos(60°-a)-V3 sina-cosa
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oganesbagoyan
Verified answer
2cos(60°-α) -√3sinα -cosα=2*(cos60°cosα +sin60°sinα) -
√3sinα -cosα =
=2* ( (1/2)*cosα +(√3/2)*sinα ) - √3sinα -cosα=cosα +√3sinα )
-
√3sinα -cosα =0.
-----
или по другому :
2cos(60°-α) -√3sinα -cosα =
2cos(60°-α) -(√3sinα +cosα ) =
2cos(60°-α) -2(√3/2sinα +(1/2)*cosα ) =2cos(60°-α) -2(sin60°*sinα +cos60°*cosα ) =2cos(60°-α) -
2cos(60°-α) =0.
2 votes
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Verified answer
2cos(60°-α) -√3sinα -cosα=2*(cos60°cosα +sin60°sinα) - √3sinα -cosα ==2* ( (1/2)*cosα +(√3/2)*sinα ) - √3sinα -cosα=cosα +√3sinα ) - √3sinα -cosα =0.
-----
или по другому :
2cos(60°-α) -√3sinα -cosα =2cos(60°-α) -(√3sinα +cosα ) =
2cos(60°-α) -2(√3/2sinα +(1/2)*cosα ) =2cos(60°-α) -2(sin60°*sinα +cos60°*cosα ) =2cos(60°-α) - 2cos(60°-α) =0.